MATHS OBJ br />
1-10: daacddcdca
11-20: bcddcdcdaa
21-30: cbbccdbaab
31-40: acdbacadbc
41-50: dbacddabbc
(1a)
142n=34base10
1*x^2+4*x^1+2*n^o=34
X^2+4x+2=34
X^2+4x-32=0
X^2+8x-4x-32=0
(X-4)(x+ =0 X-4=0 or x+8=0
X=4 or x=-8
But x can only be 4
(1b)
86.13/2.7
8613*10^2/27*10^-1 8613/27*10^-2+1
319*10^-1
3.19*10^2-1
3.19*10^1
(2a)
8/3+4/3=12/3 8/3/4*750
8/3*1/4*750/1
6000/12
500
7/3/4*750
4/3*1/4*750/1 3000/12
250
(2b)
A=P+I
I=PRT/100 where p=1250,R=3%,T=8yrs
=1250*3*8/100 =300
Amount is 1250+300
=1550
(3a)
Tn=a+(n-1)d
-118=32+(n-1)-3-118=32-3n+3
-118=35-3n
3n=153
n=153/3
n=51
Sn=n/2(2a+(n-1)d) S51=51/2(64+(50)-3)
=51/2*-86
=51*-43
=-2,193
(3b)
Tn=ar^n-1 T30=2*7^30-1
=2*7^29
(4a)
n(f)=72
n(m)=64
n(c)=62 n(fnm)=18
n(fnc)=24
n(mnc)=20
n(fnmnc)=8
U=38+34+26+10+16+12+8
=144 candidates
(4b)
5root18-3root72+4root50
5*3root2-3*6root2+4*5root2
15root2-18root2+20root2
= 17root2
NOTE THAT ROOT IS square root sign eg: 5root2
is 5_/2
(5a)
I-Nasiru is not tall
II-Victor is fat and nasiru is tall
III-Nasiru is tall or victor is fat
IV-Nasiru is tall and victor is not fat
(5b)
a=(2,-3) b=(-1, 2), c=(-2 3)
4a-3b+2c
4(2,-3) -3(-1, 2), +2(-2, 3)
(8+3-4 -12)
(7, -12)
(9a)
AO/AM=DO/BM
X+6/x=7/5
5x+30=7x
5x-7x=-30
-2x=-30 X=-30/-2
X=15m
(I) Volume=1/3pieR^2H-1/3pier^2h
1/3*22/7*7*7*21-1/3*22/7*5*5*15
1078-392.86
=685.14m^3 (II)Total surface =pieRL-pierl
22/7*7*22.1-22/7*5/7*15.8/1
486.2-248.3
=237.9m^3
(9b)
Total surface area 237.9*200
47,580.
Sent at 10:27 AM on Monday
me: (6a)
x-y/x=1, x/2+y/2=17/6
x=1+y/2 substitute equation(3) into equation(2)
x/2+y/2=17/6,x/2=17/6-y/2
1+y/2=2(17/6-y/2)
2+y/2=2(17-3y/6)
2+y=4(17-3y/6)
6(2+y)=4(17-3y)3(2+y)=2(17-3y)
6+3y=34-6y
6y+3y=34-6, 9y=28
y=28/9
from x=1+y/2
x=1+(28/9)/2=1+28/18 x=18+28/18=46/18=23/9
x=23/9, y=28/9
(6b)
(m^2-2mn+n^2)/(m^2-n^2)
(m^2-mn-mn+n^2)/(m-n)(m+n)
m(m-n)-n(m-n)/(m-n)(m+n) =(m-n)(m-n)/(m-n)
(m+n)
=m-n/m+n
(6c)
(x-2)(x-3)=12
x^2-3x-2x+6=12
x^2-5x-6=0
x^2-6x+x-6=0 x(x-6)+1(x-6)=0
(x+1)(x-6)=0
x+1=0 or x-6=0
x=-1 or x=6
(11a)
Y^2=x^2+z^2-2xzcosY =100+36-120*-cos80
=136+120*0.1736
=156.83
Y=square156.83
Y=12.52km
Distance XZ=12.52km Bearing of Z from X
X/sinX=y/sinY
10/sinX=12.52/sin100
12.52sinX=10sin100
Sinx=10sin100/12.52
Sinx=10*0.9846/12.52 Sinx=0.7866
X=sin^-1 (0.7866)
X=51.9degree
(11b)
2pier(r+h)=A
2*22/7*7(7+h)=528 44(7+h)=528
308+44h=528
44h=220
h=220/44
h=5cm
(13)
Purchase br /> 20 crate of 30 eggs per crate
@500 each=10,000
Transport=1000
Marketing ticket(50*6)=300
Total=11,300
Sales br /> 191/2 crate of @30 eggs per
crate=585eggs
Sold @ 30 per eggs=585*30=17550
Remaining eggs=1/2*30=15 eggs
Sold @ 20 per egg
15*20=#300
Total= 17850 Gross profit=17850-10000
7850
Net profit=17850-11300
=6550
Percentage profit=profit/cost
price*100/1 6550/11300*100
57.9%
Approximately 58%
(14a)
Ade= 1/2(musa), A=1/2M
M=1/2(0) A=1/2(1/2 0)= 1/4 O
A+M=114
Ade=57 years
Musa =32 years
obi=27 years
(14b) SP=N10,000
Discount= 10%
SP after discount
=10/100*(10,000)
=N1000
35%=(Sp-cp)/cp 35/100=(1000-cp)/cp
0.35cp=1000-cp
1.35cp=1000
cp=1000/1.35= N740.74
(15a)
(I)Market value=1.70 No shares bought=520
He spent 520*1.70=884
(II) A bonus of one to ten
520/10
Bonus share=52 shares
Total share held=520+52 572 shares
Dividend @ 5% of 50k
2.5k per share
Total income=2.5k*572
1430k
=#14:30
(15b)
Appreciation @ 5%
Cost, Appreciation , Value
First year: 7500, vallue 157,500
2nd year: 7875, 165,375
3rd year: 8268.75, 173643.75 4th year:
8682.19, 182,325.94
Therefore it will appreciate to
#182,325.94 at the 4th year
=====>GOOD LUCK.======
need 3000 like and share
Title : NeCO MATHER 2014 Real Answer
Description : MATHS OBJ br /> 1-10: daacddcdca 11-20: bcddcdcdaa 21-30: cbbccdbaab 31-40: acdbacadbc 41-50: dbacddabbc (1a) 142n=34base10 1*x^2+4*x^1+...
